Of course, you can do something pretty close by just having a do method:

sub foo { print "in foo" }
sub do {
   my $self = shift;
   my $meth = shift;
   $self->$meth(@_)
}

$object->do("foo", @args);
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It would have to be something that has scalar context applied to it. That would yield some neat obfu.

package Foo;

sub new { bless {}, shift }

*$_ = sub { my ($self, $arg) = @_; print "I am $_ $arg.\n" } for 1 .. 
+5;

package main;

my $foo = Foo->new;

$foo->do { @ARGV }( 'world' );
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Blammo! :-)

Being right, does not endow the right to be rude; politeness costs nothing.
Being unknowing, is not the same as being stupid.
Expressing a contrary opinion, whether to the individual or the group, is more often a sign of deeper thought than of cantankerous belligerence.
Do not mistake your goals as the only goals; your opinion as the only opinion; your confidence as correctness. Saying you know better is not the same as explaining you know better.

*$_ = sub ... doesn't work if $_ is an integer.

$_ isn't a lexical, so it doesn't get captured, producing "I am world" for output.

What's after the -> has to start with a $, so do { @ARGV } wouldn't work even if it did return a scalar.

The following works

package Foo;

sub new { bless {}, shift }

do { my $n=$_; *${\"n$n"} =
sub { my ($self, $arg) = @_; print "I am $n $arg.\n" } }
for (-1..5);

package main;

my $foo = Foo->new;

$foo->${\(n.@ARGV)}( 'world' );
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You're missing a $. It should be $f->${\("prefix_$key")}($atr);