Re^4: Dynamically constructed function calls

It would have to be something that has scalar context applied to it. That would yield some neat obfu.

package Foo;

sub new { bless {}, shift }

*$_ = sub { my ($self, $arg) = @_; print "I am $_ $arg.\n" } for 1 .. 
+5;

package main;

my $foo = Foo->new;

$foo->do { @ARGV }( 'world' );
[download]

Blammo! :-)

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Comment on Re^4: Dynamically constructed function calls Download Code

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Re^5: Dynamically constructed function calls by ikegami (Patriarch) on Nov 04, 2004 at 04:48 UTC
`$_ = sub ...` doesn't work if `$_` is an integer. `$_` isn't a lexical, so it doesn't get captured, producing "I am world" for output. What's after the `->` has to start with a `$`, so `do { @ARGV }` wouldn't work even if it did return a scalar. The following works `package Foo; sub new { bless {}, shift } do { my $n=$_; ${\"n$n"} = sub { my ($self, $arg) = @_; print "I am $n $arg.\n" } } for (-1..5); package main; my $foo = Foo->new; $foo->${\(n.@ARGV)}( 'world' );` [download]	[reply] [d/l] [select]
Re^6: Dynamically constructed function calls by ysth (Canon) on Nov 04, 2004 at 05:36 UTC
`$_ = sub ...` doesn't work if `$_` is an integer.* Not true. Did you try it? `$ perl -we'$_ = sub { print "I am 1 $_[1].\n" } for 1; $x = bless {}; + $meth = "1"; $x->$meth("world")' I am 1 world.` [download] `$_` isn't a lexical, so it doesn't get captured, producing "I am world" for output.* Correct. What's after the -> has to start with a $, so do { @ARGV } wouldn't work even if it did return a scalar. dragonchild was responding to my suggestion that ->do{} be made to work.	[reply] [d/l] [select]
Re^7: Dynamically constructed function calls by ikegami (Patriarch) on Nov 04, 2004 at 15:56 UTC
"Not true. Did you try it?" yes, I did. Perl does many odd things, so I always try things before commenting on them. I even tried a few variations. None of them worked. It works, now, though, so I must have done somethig wrong, but I can't imagine what. X_X	[reply]


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