Howdy AM,
crypt() in Perl encrypts a string exactly like crypt(3) in your C
library. Consulting your crypt(3) manpage will probably show you that if
crypt() is provided a salt that begins with the three characters '$1$' followed
by at most 8 characters, it will use an MD5-based algorigth.
Changing your code to:
my @chars = ('a'..'z', 'A'..'Z', 0..9);
my $password = do {{
local $_ = join "" => map {$chars [rand @chars]} 1..8;
redo unless /[a-z]/ && /[A-Z]/ && /\d/;
$_;
}};
my $salt = '$1$' . join '',
('.', '/', 0..9,
'A'..'Z', 'a'..'z')[ map { int rand 64 } 0 .. 7 ];
my $encrypted_pass = crypt($password, $salt);
should result in an MD5 passwd (depending on your systems crypt(3), of course).
Hope that helps,
-- dug
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