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The first numeric sort is 'numerifying' the strings and stripping the leading zeroes which messes up the rest of the routine.

I am not if that is right, at least not in the simple sense of what you say. See:

sub find_holes { my @list = @{ shift() }; @list = sort { $a <=> $b } @list; my $low = $list[0]; my $high = $list[-1]; my %isthere = map { $_ => 0 } ($low..$high); print "@{[sort keys %isthere]}\n\n"; print "@list\n\n"; $isthere{$_} = "yes" for map {$_+0} @list; my @vacancies = grep { not $isthere{$_} } sort keys %isthere; return \@vacancies; } my @issues = @{ [ '00001', '00002', '00003', '00004', # '00005', '00006', '00007', '00008', '00009', #... ] }; print join("\n", @{ find_holes( \@issues ) });


d:\tmp\try>perl perl 1 2 3 4 5 6 7 8 9 00001 00002 00003 00004 00006 00007 00008 00009 5

What the sort probably does is to fill the number entry in the glob of the entries of @list. But why does the ".." operator use the number slot, while the hash access code and print use the string slot?

Christian Lemburg
Brainbench MVP for Perl

In reply to Re: Re: Re: Finding missing elements in a sequence (code) by clemburg
in thread Finding missing elements in a sequence (code) by deprecated

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