Calling a sub resolved from a scalar read from STDIN, fixing your code a bit:
package ECHO_MODULE;
sub say_hi {print "hi\n";}
sub say_bye {print "bye\n"}
package main;
print "enter subroutine name: ";
chop ($subname = <STDIN>);
if (ECHO_MODULE->can($subname) ) {
ECHO_MODULE->$subname();
} else {
print "sub '$subname' not defined.\n";
}
Read the perl documentation, namely perlrun, perlsub, perlref... anything, all, more.
update, as per privmsg from memnoch:
For the can() method, see perlobj: it resides in the module UNIVERSAL from
which all classes implicitly inherit as their last base class. As chromatic pointed out below,
the method can() returns a subroutine reference for its argument, and calling a sub as method or function
makes a difference. ECHO_MODULE->$subname() will get ECHO_MODULE as its first argument, while
ECHO_MODULE->can($subname)->() will not. It all depends on the design of the package - is it a functional
package (a.k.a library) or a class?
--shmem
_($_=" "x(1<<5)."?\n".q·/)Oo. G°\ /
/\_¯/(q /
---------------------------- \__(m.====·.(_("always off the crowd"))."·
");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}
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