Question about two operators

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

Hi, I have two questions about perl operators that I have never used. How do these operators work (links to other sites are fine)?

<<= What does this operator do?

Also,

What would the value of the statement below be and why would one use it?

10 || 34

Thank you

Comment on Question about two operators

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Re: Question about two operators by Corion (Patriarch) on Oct 16, 2007 at 14:18 UTC
See perlop, the documentation about Perl Operators. `<<=` is the assignment variant of the left-shift operator, just like += is the assignment variant of the addition operator. `\|\|` returns the value of the leftmost expression that is true.	[reply] [d/l] [select]
Re: Question about two operators by mr_mischief (Monsignor) on Oct 16, 2007 at 14:45 UTC
Aside from what Corion said, I'll point out that one wouldn't use the expression: `10 \|\| 34` as it is written there. That will always evaluate to 10. However, you'll often see in code things like any of the following when you're not sure the value on the left will have a nonzero value. `$var \|\| 1; $foo \|\| $bar; $rock \|\|= 42; $paper \|\|= $scissors;` [download]	[reply] [d/l] [select]
Re^2: Question about two operators by mreece (Friar) on Oct 17, 2007 at 05:41 UTC
`$rock \|\|= 42;` how auspicious, because while `10 \|\| 34` is 10, `10 \| 34` is 42!	[reply] [d/l] [select]