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Re^3: call subroutines via hash

by swkronenfeld (Hermit)
on Jan 04, 2006 at 22:40 UTC ( #521042=note: print w/replies, xml ) Need Help??


in reply to Re^2: call subroutines via hash
in thread call subroutines via hash

The above note by Errto explained why \@data works. As s?he said, it creates a reference to the array @data, and stores it in the scalar.

Since you said you're confused by how both methods work, let me clear up eric256's method.

$array_ref = [ ]; creates a new, empty array, and returns the reference to it. In this case, we assign it to $array_ref.
$array2_ref = [1, 2, 3, 4]; creates a new array and initializes it with the values supplied. It returns the reference, which we once again store.
$radius_ref = [@data] will create a new array initialized with the contents of @data.

There's a really important distinction between using [@data] and \@data. They both create array references, but the method with the brackets creates a new array, while the slash method references your existing array. The example below should clear up any confusion you have.

my @data = (1,2,3,4); my $existing_ref = \@data; my $new_ref = [@data]; $existing_ref->[0] = "a"; $new_ref->[2] = "c"; Now, @data contains (a,2,3,4) and $new_ref points to an array the contains (1,2,c,4)

Hope that helped.

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