Re^2: Reverse engineering regular expressions

I found a better module on CPAN that does exactly what I need Parse::RandGen::Regexp.pm. Thanks for all the input guys.

The problem I'm having now is how to get a regexp into this function. I wrote a stub progam to test.

#!/usr/bin/perl -w

use strict;
use Parse::RandGen::Regexp;

my $regexp = "/^STOR\s^\n{100}/smi";
my $r = Parse::RandGen::Regexp->new($regexp);
my $string = $r->pick(match=>1, captures=>{}); 
print("\$string: $string\n");

This throws the following error.

Unrecognized escape \s passed through at ./regexp2.pl line 6.
%Error:  Parse::RandGen::Regexp has an element that is not a Regexp reference (ref="")! at /usr/lib/perl5/site_perl/5.8.6/Parse/RandGen/Regexp.pm line 36
	Parse::RandGen::Regexp::_newDerived('Parse::RandGen::Regexp=HASH(0x9dcdd88)', 'HASH(0x9e5f138)') called at /usr/lib/perl5/site_perl/5.8.6/Parse/RandGen/Condition.pm line 81
	Parse::RandGen::Condition::new('Parse::RandGen::Regexp', '/^STORs^\x{a}{100}/smi') called at ./regexp2.pl line 7

Now I need the string in regexp format to pass to the function. I could just put the string in qr//s but in my real program I need to read the regexps from a list so they will come in scalar format.

i.e. How do I convert:

"/^STOR\s^\n{100}/smi";

qr/^STOR\s^\n{100}/smi

I'm not sure how to do this conversion.

Thanks,

Comment on Re^2: Reverse engineering regular expressions

Replies are listed 'Best First'.
Re^3: Reverse engineering regular expressions by CountZero (Bishop) on Aug 06, 2005 at 16:19 UTC
This is a duplicate of my answer to Parse::RandGen::Regexp As the `qr//` method runs in interpolative context one can do `use strict; my $match='test'; my $regex_match=qr/$match/i; my $test_value='This is a Test'; print 'It matches' if $test_value=~m/$regex_match/;` [download] CountZero "If you have four groups working on a compiler, you'll get a 4-pass compiler." - Conway's Law	[reply] [d/l] [select]


Perl-Sensitive Sunglasses
	PerlMonks