Re^2: Is it possible to store an arthimetric operator in a variable?

You shouldn't use prototypes unless necessary, because of their side-effects. In this case, the prototype isn't even being checked because you're using a reference to the function.

sub test($) { print("Boo!\n"); }

my $f = \&test;
$f->();         # No error. Prints "Boo!".
$f->(1, 2, 3);  # No error. Prints "Boo!".
[download]

And why bother with ?1:0 and ?0:1 since == already returns a boolean value.

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Re^3: Is it possible to store an arthimetric operator in a variable? by Adam (Vicar) on Jul 19, 2005 at 15:18 UTC
You are correct that the code isn't using the prototypes or requires the 1:0. I used them both, however, to be very clear to our anonymous reader what it was the code was doing. Also, I used 1:0 because I don't like using undef as a boolean false; it's not relevant here, but I find that 0 as false makes debugging easier which has led to this habit.	[reply]
Re^4: Is it possible to store an arthimetric operator in a variable? by ikegami (Patriarch) on Jul 19, 2005 at 15:22 UTC
Boolean false isn't undef. Notice the lack of warnings in the following snippet: `>perl -we "print(1==2)" >` [download]	[reply] [d/l]
Re^5: Is it possible to store an arthimetric operator in a variable? by Adam (Vicar) on Jul 19, 2005 at 15:23 UTC
Sorry, you are right. It's "", which is just as useless in debugging... (it's been so long that I wrote a boolean function where I didn't use 0 that I forgot. Thank you.)	[reply]
Re: Is it possible to store an arthimetric operator in a variable? by benizi (Hermit) on Jul 20, 2005 at 19:17 UTC


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