Assuming one ball is heavier than the other 11
0. Divide balls into sets of 6. Weigh on a balance and select the heavier set.
1. Divide the heavier set into sets of 3. Weigh on a balance and select the heavier set.
2. Take two balls from the heavier set. Weigh on a balance. Select the heavier ball. If the two balls are equal, the third ball from the set is heavier.
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Unfortunately, you don't know if the ball is heavy or light. A solution set has multiple outcomes but there are at least two solution sets that I have thought of. The Monastery now supports real spoiler tags by the way.
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