Re: Assigning an array to a scalar

My poor effort. Seeing as map was already used I went for while / shift.

while ($_ = shift @letters) { $word .= $_; }
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I thought shift should return the array element, so why do I need to use $_ = shift ... ?

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Re^2: Assigning an array to a scalar by ysth (Canon) on Sep 26, 2004 at 06:53 UTC
I thought shift should return the array element, so why do I need to use $_ = shift ... ? Because the implied $_ = in a while condition only happens for readline aka <>. Also, with shift you don't get the implied defined() around the while condition; if one if the elements of @letters is "0", the loop will stop early. Try `while (defined($_ = shift @letters))`	[reply] [d/l]


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