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Re: Re: Re: Implement uclast with a regex

by UnderMine (Friar)
on Mar 10, 2004 at 10:39 UTC ( [id://335406]=note: print w/replies, xml ) Need Help??


in reply to Re: Re: Implement uclast with a regex
in thread Implement uclast with a regex

use Benchmark; my $tests = [qw(these are a few test to try andaverylongteststring acoupleoftimesover xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx +xxxxxxxxxxxxxxxxxxxxxxxxxx zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz +zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz zzzzzzzzzzzzzzzzzzzzzzzzzzzzz)]; timethese (100000, { NoOpLoop => sub { for my $test (@$tests) { # NO Op Loop } }, regex1 => sub { for my $test (@$tests) { $test=~s/^(.*)(.)$/\L$1\U$2/; } }, substr => sub { for my $test (@$tests) { $test= lc(substr($test, 0, length($test)-1)) . uc(substr($test, -1, 1)); } }, reverse=> sub { for my $test (@$tests) { $test=reverse ucfirst lc reverse $test; } } });
and the winner is :-
Benchmark: timing 100000 iterations of NoOpLoop, regex1, reverse, subs +tr... NoOpLoop: 2 wallclock secs ( 1.86 usr + 0.00 sys = 1.86 CPU) @ 53763.44/s (n=100000) regex1: 82 wallclock secs (30.31 usr + 0.01 sys = 30.32 CPU) @ 3298.15/s (n=100000) reverse: 8 wallclock secs ( 7.40 usr + 0.00 sys = 7.40 CPU) @ 13513.51/s (n=100000) substr: 8 wallclock secs ( 8.51 usr + 0.01 sys = 8.52 CPU) @ 11737.09/s (n=100000)
Interesting: double reverse seamed the best but as always test on real data!!

Hope it helps
UnderMine

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