Hrm. That's just an edge case, and will only happen when you find that the palindrate($N) is greater than $N. In those cases, '9'x(length($N)-1) would exceed the decrimented '0990' value.
I'm still thinking out loud at this stage, but it doesn't seem like you'd have to iterate at all, to find provably close palindromic numbers.
-- [ e d @ h a l l e y . c c ]
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