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Regarding: Well, I thought doing a s//e on it would be the ticket, but apparently not.

It takes a little extra work, but it is certainly do-able...

#!/usr/bin/perl -w use strict; my $find = 'proof(\S+)'; my $rpl = '"read$1"'; my $text = 'proofing is proof it needed to be proofed'; if ($text =~ s/$find/$rpl/ee) { print "1st replacement made:\n\t$text\n"; }
The double /ee is needed. The first /e sub's in the value of $rpl. The second /e evaluates that and DWIM's.

The nested quotes are needed in defining $rpl because without the inner double-quotes, the second /e fails. Another way to do that bit (and this may help in understanding) would be: my $rpl  = '"read" . $1'; You have to get both the quoting and the /ee right for the thing to work as intended.

HTH

------------------------------------------------------------
"Perl is a mess and that's good because the
problem space is also a mess.
" - Larry Wall


In reply to Re: Re: evaluating $1 in a replace string by dvergin
in thread evaluating $1 in a replace string by Oaks

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