Here is another complicated "perlish" solution to avoid simple C-style loops as proposed above (and which is the most sensible approach IMHO), this time using closures:
se warnings;
use strict;
sub create_scheduler {
my $list = shift;
return sub {
my $i = shift;
return () if $i > $#$list - 1 or $i < 0;
return ( $list->[$i], $list->[$i+1] );
}
};
my $leg = create_scheduler [ "Chicago", "Saint Looey", "Joplin", "OKC"
+, "Amarillo", "Gallup", "Flagstaff", "Winona", "Kingman", "Barstow",
+"San Bernandino", "LA" ];
my $i = 0;
while( my @pair = $leg->($i++) ) {
print join( " to ", @pair ), "\n";
}
You could also "enclose" the index into the closure if you want to create a one-time iterator over your array.
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