Re: Re: Zero Padding to the Right of the Decimal

I agree whole-heartedly, the number probably shouldn't be baked into a format until you plan to display it. <insert standard disclaimer about being appropriate for the rest of your script and your coding style>

So it might look like this with only one print/printf/sprintf:

my $i=0;
while ($i <=100){
    $i=$i+0.01;
    printf("%3.2f\n",$i);
}
[download]

-Kurt

Comment on Re: Re: Zero Padding to the Right of the Decimal Download Code

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Re: Re: Re: Zero Padding to the Right of the Decimal by Cody Pendant (Prior) on Jan 15, 2004 at 20:40 UTC
Just one more thing, how about this: `printf( "%3.2f\n" , ($i + 0.01) );` [download] Instead of the two lines above? ($_='kkvvttuubbooppuuiiffssqqffssmmiibbddllffss') =~y~b-v~a-z~s; print	[reply] [d/l]
Re: Re: Re: Re: Zero Padding to the Right of the Decimal by boo_radley (Parson) on Jan 15, 2004 at 20:54 UTC
you'll never exit the loop that way, because you never modify $i. You could use +=, though : `my $i=0; while ($i <=100){ printf("%3.2f\n",$i+=0.01); }` [download]	[reply] [d/l]
Re: Re: Re: Re: Re: Zero Padding to the Right of the Decimal by revdiablo (Prior) on Jan 15, 2004 at 21:54 UTC
This thread is probably already too deep for anyone to care, but if I were doing this, I would do so thusly: `printf "%3.2f\n", $_/100 for 0 .. 100*100;`	[reply] [d/l]
Re: Re: Re: Re: Zero Padding to the Right of the Decimal by Not_a_Number (Prior) on Jan 15, 2004 at 20:59 UTC
`printf( "%3.2f\n" , ($i + 0.01) );` doesn't work. Change to: `printf( "%3.2f\n" , ($i += 0.01) );` dave	[reply] [d/l] [select]


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