### Re: challenge: OEIS A073015 serie

by danaj (Friar)
 on Dec 18, 2015 at 12:44 UTC ( #1150692=note: print w/replies, xml ) Need Help??

in reply to challenge: OEIS A073015 serie

Without using a bigint module, you can't generate much of the series. I suspect correct Perl 6 solutions would be really easy.

```use bigint; my \$f=3; for (1..12) { \$f = (\$f-1)**2 if \$_>1; say \$f }
# Faster: replace bigint with Math::GMP qw/:constant/;

I admit I find code golf to be tiresome, and prefer readable and efficient solutions.

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Re^2: challenge: OEIS A073015 serie
by Laurent_R (Canon) on Dec 18, 2015 at 23:11 UTC
I suspect correct Perl 6 solutions would be really easy.
Yes, indeed, really easy in Perl 6, except that you can't seem to get to infinity. ;-) So there is a need for some other way of stopping the calculation than just looking for /inf/ or the like.

In fact, it is so easy that I just needed to copy and paste your code and run it with Perl 6/Rakudo:

```\$ perl6 -e 'my \$f=3; for (1..16) { \$f = (\$f-1)**2 if \$_>1; say \$f }'
3
4
9
64
3969
15745024
247905749270529
61457260521381894004129398784
...
The full output for those interested with big nums (adding an extra newline between the numbers for a better clarity of output) is given below: The last number above has more than 7300 digits. The whole one-liner script executes in less than 1 second, but it starts to show a noticeable slow down when getting above 16.
Re^2: challenge: OEIS A073015 serie
by Anonymous Monk on Dec 18, 2015 at 17:10 UTC

Trolling season!

perl -E 'say(eval),\$,.=\$#\$,\$,x=eval,redo,for\$,="+3"'

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