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Re^2: Python 'is' commandby syphilis (Archbishop) |
| on Aug 16, 2019 at 11:21 UTC ( [id://11104563]=note: print w/replies, xml ) | Need Help?? |
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All the solutions shown in this thread involving references are not general enough due to wrong assumptions, see FAQ in Object::ID. Really ? ... *all* of them ? I think the OP is concerned about determining whether 2 existent objects are the same, not whether a current object has the same "address" as an obsolete one. So long as 2 reference addresses of currently existent objects are being compared, then I don't really see the relevance of the FAQ in Object::ID. Cheers, Rob
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