Re: Re: Re: 0**0

in reply to Re: Re: 0**0
in thread 0**0

0/-infinity, which is just another indeterminate.

Actually, 0/-infinity equals 0. It's not indeterminate. An indeterminate division would be something like infinity/infinity.

buckaduck

Comment on Re: Re: Re: 0**0

Replies are listed 'Best First'.
Re: Re: Re: Re: 0**0 by Arien (Pilgrim) on Jan 17, 2003 at 07:38 UTC
Actually, 0/-infinity equals 0. It's not indeterminate. Actually, the limit of 0/x as x goes to -∞ is 0. Infinity is not a number, it's a concept. An indeterminate division would be something like infinity/infinity. The limit for x to ∞ of x/x is 1. — Arien	[reply]
Re^5: 0**0 by Aristotle (Chancellor) on Jan 18, 2003 at 17:04 UTC
lim[x → ∞](x/x) = 1 lim[x → ∞](2x/x) = 2 Now which one do we take? Makeshifts last the longest.	[reply]
Re^6: 0**0 by Arien (Pilgrim) on Jan 19, 2003 at 12:52 UTC
lim _{x → ∞} x/x was just an example to show that dividing two numbers that approach infinity is determinate. I didn't mean to suggest that the "division" of infinity by infinity has the value 1 (or 2, or any value for that matter). — Arien	[reply]