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Re: Re: Re: Re: 0**0

by Arien (Pilgrim)
on Jan 17, 2003 at 07:38 UTC ( [id://227625]=note: print w/replies, xml ) Need Help??


in reply to Re: Re: Re: 0**0
in thread 0**0

Actually, 0/-infinity equals 0. It's not indeterminate.

Actually, the limit of 0/x as x goes to -∞ is 0. Infinity is not a number, it's a concept.

An indeterminate division would be something like infinity/infinity.

The limit for x to ∞ of x/x is 1.

— Arien

Replies are listed 'Best First'.
Re^5: 0**0
by Aristotle (Chancellor) on Jan 18, 2003 at 17:04 UTC
    lim[x → ∞](x/x) = 1
    lim[x → ∞](2x/x) = 2

    Now which one do we take?

    Makeshifts last the longest.

[reply]

      lim x → ∞ x/x was just an example to show that dividing two numbers that approach infinity is determinate. I didn't mean to suggest that the "division" of infinity by infinity has the value 1 (or 2, or any value for that matter).

      — Arien

[reply]

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