Re^2: How do I pretend a reference isn't a reference

in reply to Re: How do I pretend a reference isn't a reference
in thread How do I pretend a reference isn't a reference

How is that possible? Sure you can redefine _, but that won't do any blessing at compile time.

Quite possible. My webapp is large, and runs within mod_perl, so I have an initialisation process which loads most required modules at the beginning. In my i18n class, which gets loaded as early as possible, I have this code:


    {
        no warnings 'redefine';

        sub compile_mode {
            *::_ = sub { i18n::String->new(@_) };
        }

        sub run_mode {
            *::_ = sub { $i18n::Current_Lang->maketext(@_) };
        }
    }

    BEGIN {
        compile_mode();
    }
[download]

Once initialisation is finished, my loader calls i18n::run_mode. If I need to require any large modules that belong to my app during runtime, instead of using the require builtin, I call i18n::i18n_require('Module::Name'):


    sub i18n_require {
        my $original = my $path = shift;
        i18n::compile_mode();
        $path=~s{::}{/}g;

        my $error;
        eval {require $path.'.pm'}
         or $error = $@ || 'Unknown error';
        
        i18n::run_mode();

        die( sprintf( "Error loading '%s' at %s line %d:\n%s\n",
                      $original, (caller)[ 1, 2 ], $error
             )
        ) if $error;

        return $INC{$path};
    }
[download]

I tried overriding UNIVERSAL::require, but certain modules outside my control didn't appreciate that. Anyway, doing it this way is explicit, and only a few characters more.

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Re^3: How do I pretend a reference isn't a reference by Anonymous Monk on Nov 06, 2008 at 12:48 UTC
I was thinking `use yourblah; my $foo = _('this is blahblah');` [download] at compile time, $foo doesn't get blessed.	[reply] [d/l]
Re^4: How do I pretend a reference isn't a reference by clinton (Priest) on Nov 06, 2008 at 12:54 UTC
It depends what `sub _` is defined to be, at compile time :) Check my code in Re^2: How do I pretend a reference isn't a reference and you'll see that `$foo` WOULD contain an object there.	[reply] [d/l] [select]
Re^5: How do I pretend a reference isn't a reference by clinton (Priest) on Nov 06, 2008 at 14:37 UTC
That's not what my code does, nor was I saying that $c was one thing at compile time and one at run time. This is what I do: `# init the app sub _ { 'compile time '.@_}; my $compile = _(1); sub foo { _(1) }; # finished compiling, so redefine sub _ sub _ { 'run time '.@_}; # run the code my $run = foo(); print " $compile - $run\n" __END__ compile time 1 - run time 1` [download] UPDATE: Meant to reply to Re^5: How do I pretend a reference isn't a reference	[reply] [d/l]
Re^5: How do I pretend a reference isn't a reference by Anonymous Monk on Nov 06, 2008 at 14:00 UTC
No it doesnt. `sub _ { 'compile time '.@_}; local *_ = sub { 'run time '.@_}; # the above is what your module/init code does my $c = _(1); die $c; __END__ run time 1 at - line 6.` [download] You were saying that $c is one thing at runtime, another at compile time. Its only something at runtime.	[reply] [d/l]

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