in reply to Re: quick question about hash element access
in thread quick question about hash element access
And with very few changes you can make it an lvalue, so you can use it to assign to:
sub nested : lvalue { @_ == 1 ? $_[0] : nested($_[0]{$_[1]}, @_[2..$#_]); }
..and now you can say:
nested(\%hash, a => b => c =>) = "VALUE";TThis can lead to such fun looking constructs as nested $hashref, a => b => c => d => = 42; Note that this code will only work under perl 5.6.0 or later, though; earlier perls had more restricted definitions of lvalues. See also descending a tree of hash references.
perl -pe '"I lo*`+$^X$\"$]!$/"=~m%(.*)%s;$_=$1;y^`+*^e v^#$&V"+@( NO CARRIER'
|
---|
In Section
Seekers of Perl Wisdom