Re: Calling subroutine with a scalar

http://qs321.pair.com?node_id=1125883

in reply to Calling subroutine with a scalar

Try

my $res = new Some::Package({ foo => bar })->$sub;

Or better:

my $res = Some::Package->new({ foo => bar })->$sub;

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Re^2: Calling subroutine with a scalar by Rodster001 (Pilgrim) on May 06, 2015 at 18:53 UTC
That did it. Thank you. Why is it better to call new that way?	[reply]
Re^3: Calling subroutine with a scalar by jeffa (Bishop) on May 06, 2015 at 18:58 UTC
You can learn why here: http://modernperlbooks.com/mt/2009/08/the-problems-with-indirect-object-notation.html jeffa L-LL-L--L-LL-L--L-LL-L-- -R--R-RR-R--R-RR-R--R-RR B--B--B--B--B--B--B--B-- H---H---H---H---H---H--- (the triplet paradiddle with high-hat)	[reply] [d/l]

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