> It does not mention $# at all
well in these 5.20 docs this is mentioned
$aref->$#*; # same as $#{ $aref }
> but points 1 and 2 there address exactly what you are asking about.
Anywhere you'd put an identifier (or chain of identifiers) as part of a variable or subroutine name
So I suppose $# counts as a special function since its not a variable, but addressing an attribute of a variable?
Thanks anyway! :)
Cheers Rolf
(addicted to the Perl Programming Language and ☆☆☆☆ :)
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Special function? No.
The a in @a is the identifier part of the variable name; the documentation addresses anywhere you'd put that a, which includes $#a.
Update: hmm, it does say "as part of a variable...name", implying it would only work if $#a is a considered a variable. I shy away from that because, even though it is an assignable lvalue, it really is just an attribute of an array variable. So the doc could use a minor tweak.
In any case, $#$arrayref / $#{$arrayref} ought to be added to the examples there.
--
A math joke: r = | |csc(θ)|+|sec(θ)| |-| |csc(θ)|-|sec(θ)| |
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> I shy away from that because, even though it is an assignable lvalue, it really is just an attribute of an array variable. So the doc could use a minor tweak.
That's my point, I couldn't mentally map this behavior to normal dereferencing mechanics cause it rather feels like a magic feature.
To make it more obvious, theoretically we could have a special syntax for keys and values of a hash ( like e.g. %<hash ).
This would be a similar beast (/me struggling for a name ;)
> In any case, $#$arrayref / $#{$arrayref}ought to be added to the examples there
Definitely!
Cheers Rolf
(addicted to the Perl Programming Language and ☆☆☆☆ :)
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$#a is no more a function and as much a variable as $a and @a.
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