in reply to Why does foo() evaluate in array context in "${\foo()}"?
How would you do this:
sub foo { \('fred', 'bill') };; print "${ foo() }";; bill
if a scalar context was implied by "${ ... }"?
No. I can't think of a good use for it either :)
But given you have scalar to force a scalar context, but no list to do the opposite, the status quo gives the greatest flexibility. Whether there is a good use for that flexibility it was (still is) too early to judge :)
Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
"Science is about questioning the status quo. Questioning authority".
In the absence of evidence, opinion is indistinguishable from prejudice.
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