in reply to Re: Re: Re: Filthy Floats
in thread Filthy Floats
I am finding it hard to believe that Perl can't represent 0.98
printf("%.25f\n", 0.98);
It's not perl, it's the underlying floating points which can not precisely represent 0.98, this is due to floating point numbers being base 2 and having a finite size.
printf("%.25f\n", 0.98);
It's not perl, it's the underlying floating points which can not precisely represent 0.98, this is due to floating point numbers being base 2 and having a finite size.
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