Re: Regex help

/B@{[join('|', 38..49)]}/
or
/B(?:38|39|40|41|42|43|44|45|46|47|48|49)/
or
/B(\d\d)/ && $1 >= 38 && $1 <= 49

Comment on Re: Regex help Select or Download Code

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Re^2: Regex help by ikegami (Patriarch) on Oct 25, 2004 at 22:37 UTC
or `/B(?:3[89]\|4\d)/` or `/B(?!3[0-7])[34]\d/` or `/B(\d\d)(?(?{ $1 < 38 \|\| $1 > 49 })(?=A)(?=Z))/`	[reply] [d/l] [select]
Re^3: Regex help by C_T (Scribe) on Oct 26, 2004 at 17:44 UTC
`/B(?:3[89]\|4\d)/` [download] This worked like a charm, and really helped me understand the proper syntax of the conditional test. Thanks much! CT Charles Thomas Madison, WI	[reply] [d/l]
Re^4: Regex help by ikegami (Patriarch) on Oct 26, 2004 at 18:27 UTC
`(?(?{code}true-regexp) (?(?{code}true-regexp\|false-regexp) / B (\d\d) (? (?{ $1 < 38 \|\| $1 > 49 }) # if invalid (?=A)(?=Z) # then fail # else succeed ) /x` [download] It could also have been written: `/ B (\d\d) (?(?{ $1 >= 38 && $1 <= 49 }) # if valid # succeed \| # else (?=A)(?=Z) # fail ) /x` [download] `(?=A)(?=Z)` means the next char must be an 'A' and must be a 'Z'. That's never gonna happen.	[reply] [d/l] [select]