Re: how do I use a hash of hashes reference to a function ?

in reply to how do I use a hash of hashes reference to a function ?

You may wish to wrap your code in <code> tags next time. I'm not 100% sure what you're asking, but perhaps this code example will answer your question:

sub function {
   my $hashref = shift;

   $hashref->{three} = 3;
}

my %hash = ( one => 1, two => 2 );
&function(\%hash);
print join(", ", keys %hash);   # one, two, three
[download]

You can also have the same behavior like this:

sub function (%) {
   my %hashref = shift;
   ...
}

&function(%hash);       # passes %hash as a ref
[download]

Then there's this:

sub function {
   my %hash = %{shift};   # de-references

   $hash{three} = 3;      # Does not affect the real %hash!
}
[download]

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RE: Answer: how do I use a hash of hashes reference to a function ? by Fastolfe (Vicar) on Sep 22, 2000 at 02:31 UTC
Sorry, I neglected to read your title very well and did not take this one step further: `%hash = ( one => { a => 10, b => 20 }, two => { c => 30, d => 40 } ); &function(\%hash); sub function { my $hash = shift; $hash->{two}->{d} = 50; # changes 'd' }` [download] You can go as deep as you want here with hashes of hashes of hashes. Hope that helps...	[reply] [d/l]

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