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in reply to Re: Re: look-behind regex
in thread look-behind regex

How about s/(toto)|foo/$1||'bar'/e

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Re: Re: Re: Re: look-behind regex
by Anonymous Monk on Jul 25, 2002 at 15:18 UTC
    TMTOWTDI...

    But the reason I used defined() was that I wanted to give a general solution. Someone might copy the code and change toto to something else that matches something that is false without reflecting on how it works. Or you might change it yourself later. Then you perhaps abstract the pattern, and suddenly you have a hard-to-trace bug. I always try to code so that I don't bite myself later on when I patch my code.

    Cheers,
    -Anomo
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      In this case, it's easy enough to ensure that $1 is not false. Even if zejames had wanted 'foo' not preceeded by '0' you could substitute  s/(0.*foo)|foo/($1,'bar')[!$1]/es
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