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in reply to Re: RegEx Challenge
in thread RegEx Challenge

The look-behind. It looks at the original scalar rather then the modified. It makes sense, but it could really go either way.

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Re: Re: Re: RegEx Challenge
by japhy (Canon) on May 03, 2002 at 21:46 UTC
    Ah yes, that. I've witnessed people getting bitten by that.

    _____________________________________________________
    Jeff[japhy]Pinyan: Perl, regex, and perl hacker, who'd like a (from-home) job
    s++=END;++y(;-P)}y js++=;shajsj<++y(p-q)}?print:??;

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