Re: How the auto-increment operator works?

Wait please help me with this again, I don't get why print ++($foo = "Zy"); prints "Zz" and not "Az". Isn't the uppercase "Z" a limit?

And I don't get what "wrap" means either because english is not my native language.

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Re^2: How the auto-increment operator works? by choroba (Cardinal) on Aug 04, 2020 at 23:48 UTC
It's similar to `print ++($foo = 98)` [download] which returns 99. Similarly, in "Zy", it first tries to increment from the right, and `y -> z` is a valid increment which finishes the operation. The next word would be AAa, because "z" goes to "a" with a "carry flag", so we need to increment "Z", which goes to "A" with a carry flag, and as there's nothing else to increment to the left, we add "A" (the case is copied from the previous letter). Wrap means "to start the round from the beginning again" here. `map{substr$_->[0],$_->[1]\|\|0,1}[\\|\|{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^ARGV,3]`	[reply] [d/l] [select]
Re^3: How the auto-increment operator works? by zapdos (Sexton) on Aug 04, 2020 at 23:53 UTC
Thank you very much brother ;-)	[reply]
Re^2: How the auto-increment operator works? by LanX (Saint) on Aug 04, 2020 at 23:54 UTC
> And I don't get what "wrap" means The "positions" rotate like in a mechanical calculator, only difference some have characters instead of digits. Whenever one wheel finished a full rotation it'll increment the next one to the left. Anyway we told you already and I'm tired of this now. Cheers Rolf _{(addicted to the Perl Programming Language :) Wikisyntax for the Monastery}	[reply]
Re^3: How the auto-increment operator works? by zapdos (Sexton) on Aug 05, 2020 at 00:59 UTC
Thank you very much again bro ^_^	[reply]