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in reply to Mini-Tutorial: Dereferencing Syntax

Not mentioned:   $$foo as shorthand for $foo->.
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Re^2: Mini-Tutorial: Dereferencing Syntax
by ikegami (Patriarch) on Sep 17, 2012 at 05:03 UTC

    $$foo is not a shorthand for $foo->. 

    >perl -E"$foo=\'foo'; say $$foo;"
foo

>perl -E"$foo=\'foo'; say $foo->;"
syntax error at -e line 1, near "->;"
Execution of -e aborted due to compilation errors.

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    You're probably thinking of the equivalency of $$foo[...] and $foo->[...] and of $$foo{...} and $foo->{...}, but that's already mentioned.

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