Re^3: Understanding Split and Join

in reply to Re^2: Understanding Split and Join
in thread Understanding Split and Join

Looks like a case to be fixed either in the docs or in the code of the Perl interpreter itself

I'm not sure what you mean by "fixed"? split doesn't have the special logic for // that match and substitution do, but even those operations don't have special logic for / /x, / # /x or / (?#)/x.

Comment on Re^3: Understanding Split and Join

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Re^4: Understanding Split and Join by ferreira (Chaplain) on Jan 02, 2007 at 11:01 UTC
I think I have misunderstood that behavior: `$ perl -e '@a = split //, 'abc'; print "@a"' a b c $ perl -e '@a = split / /x, 'abc'; print "@a"' a b c $ perl -e '@a = split / # /x, 'abc'; print "@a"' a b c $ perl -e '@a = split / (?#) /x, 'abc'; print "@a"' a b c` [download] The logic of split does not need to be special for this to work. These are real empty patterns and `split` understand they are meant to split characters as they return empty delimiters. But you were saying that the same is not automatic for patterns equivalente to `/^/`. Sorry for the confusion I made.	[reply] [d/l] [select]

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Re^4: Understanding Split and Join
by ferreira (Chaplain) on Jan 02, 2007 at 11:01 UTC

$ perl -e '@a = split //, 'abc'; print "@a"'
a b c

$ perl -e '@a = split / /x, 'abc'; print "@a"'
a b c

$ perl -e '@a = split / # /x, 'abc'; print "@a"'
a b c

$ perl -e '@a = split / (?#) /x, 'abc'; print "@a"'
a b c
[download]

The logic of split does not need to be special for this to work. These are real empty patterns and split understand they are meant to split characters as they return empty delimiters. But you were saying that the same is not automatic for patterns equivalente to /^/. Sorry for the confusion I made.

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