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in reply to Re: need regular expression
in thread need regular expression

This formula is simpler than the one earlier. The main insight here is to avoid strings; it is better to use arithmetic addition to construct the 'year' string (i.e. 20xx) .
for ( my @dates = qw( 4-10-31 14-11-31 ) ) { s/ ^ (\d{1,2}) ((?:-\d{1,2}){2}) $ /(2000+$1).$+/xe and print; }

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Re^3: need regular expression
by Perl Mouse (Chaplain) on Nov 02, 2005 at 11:13 UTC
    I prefer to use strings - in that case, it becomes easy to deal with 3 or 4 digit years as well:
    my @dates = qw /4-10-31 14-11-31 1979-10-10/; for (@dates) { s/(\d+)/substr("2000", 0, -length($1)).$1/e; print "$_\n"; } __END__ 2004-10-31 2014-11-31 1979-10-10
    Perl --((8:>*