Re: ASCII Pattern - Golf (Russ: 83)

I can get 83:

$i=9;do{print((map{(sort map{abs}$_-$ARGV[0],$i-$ARGV[1])[-1]}1..9),"\
+n")}while--$i
[download]

Comment on Re: ASCII Pattern - Golf (Russ: 83) Download Code

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Re: Re: ASCII Pattern - Golf (Russ: 77) by Russ (Deacon) on Sep 19, 2003 at 02:57 UTC
Okay, now 77 (if you don't miss the trailing newline): `$i=9;do{print"\n",map{(sort abs$_-$ARGV[0],abs$i-$ARGV[1])[-1]}1..9}wh +ile--$i` [download] Russ	[reply] [d/l]
Re: ASCII Pattern - Golf (Russ: 77) by cLive ;-) (Prior) on Sep 19, 2003 at 03:52 UTC
74 :) `$i=9;do{print$/,map{(sort abs$_-$ARGV[0],abs$i-$ARGV[1])[1]}1..9}while +--$i` [download]	[reply] [d/l]
Re: Re: ASCII Pattern - Golf (The Sidhekin: 70, or no, 69) by Sidhekin (Priest) on Sep 19, 2003 at 22:56 UTC
A for-loop is usually shorter than a do{...}while-loop. 70 :-) `$t=abs$ARGV[1]+$_,print$/,map{(sort$t,abs$ARGV[0]-$_)[1]}1..9for-9..-1` If you want the newlines "right", I end up at 72: `$t=abs$ARGV[1]+$_,print map((sort$t,abs$ARGV[0]-$_)[1],1..9),$/for-9..-1` Update: Well, what do you know ... the string `$ARGV[1]+$_` is longer than the strings `($s=pop)` and `$s` taken together. Make those 69 and 71 (both with tie-breaker at 30 different characters): `$t=abs,print$/,map+(sort$t,abs$ARGV[0]-$_)[1],1..9for($s=pop)-9..$s-1` ... and ... `$t=abs,print map((sort$t,abs$ARGV[0]-$_)[1],1..9),$/for($s=pop)-9..$s-1` The Sidhekin `print "Just another Perl ${\(trickster and hacker)},"`	[reply] [d/l] [select]