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So do I, but $n = scalar foo does something completely different from $n = () = foo.

Observe, I have nothing up my sleeve!

sub foo { 5, 17 } # sub returning 2 values my $n1 = () = foo; # $n1 == 2 my $n2 = scalar foo; # $n2 == 17

You forgot the general rule about converting a list to a scalar: "there is no general rule for converting a list to a scalar"!


In reply to Re: Count the number of return values from a subroutine by ariels
in thread Count the number of return values from a subroutine by dkubb

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