Is there a reason you are using hashes and not arrays? I ask because your keys are only numbers, and nearly sequential numbers at that - this would seem to be the classic example of when to use arrays.
But, assuming you want to do this with hashes, you would first iterate over a sorted key list (see the FAQ How do I sort a hash (optionally by value instead of key)?) and then iterate over that list and output your desired result (How do I process an entire hash?). Something like:
#!/usr/bin/perl
use strict;
use warnings;
use Data::Dumper;
my %hash1 = ("1", "20",
"2", "20",
"4", "19",
"5", "20",
"6", "18");
my %hash2 = ("1", "19",
"2", "20",
"4", "16",
"5", "19",
"6", "20");
my %differences;
for my $key ( sort {$a <=> $b} keys %hash1) {
$differences{$key} = $hash1{$key} - $hash2{$key};
print "$key ($hash1{$key} - $hash2{$key}) = $differences{$key}\n";
}
print "\n", Dumper \%differences;
__END__
1 (20 - 19) = 1
2 (20 - 20) = 0
4 (19 - 16) = 3
5 (20 - 19) = 1
6 (18 - 20) = -2
$VAR1 = {
'6' => -2,
'4' => 3,
'1' => 1,
'2' => 0,
'5' => 1
};
and using arrays instead:
#!/usr/bin/perl
use strict;
use warnings;
use Data::Dumper;
my @array1 = (undef,20,20,19,20,undef,18);
my @array2 = (undef,19,20,16,19,undef,20);
my @differences;
for my $i (0 .. $#array1) {
next unless defined $array1[$i];
$differences[$i] = $array1[$i] - $array2[$i];
print "$i ($array1[$i] - $array2[$i]) = $differences[$i]\n";
}
print "\n", Dumper \@differences;
__END__
1 (20 - 19) = 1
2 (20 - 20) = 0
4 (19 - 16) = 3
5 (20 - 19) = 1
6 (18 - 20) = -2
$VAR1 = [
undef,
1,
0,
3,
1,
undef,
-2
];
Update: Added storage of differences
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