comment on

Hi! I don't have extensive experience with sorting methods, but in this case I think a simple approach would work, like that:

use strict;
use warnings;

my $Line;           # one input line
my @SortedData;     # resulting sorted data set

# data set example
my @Data    =   (
                    '100644:MWTP_CAT:12002: SERVER:pid=14520:Execution
+ time:TPR015-10:(millisec):53',
                    '100644:MWTP_CAT:12002: SERVER:pid=15866:Execution
+ time:TPR015-10:(millisec):10',
                    '100644:MWTP_CAT:12002: SERVER:pid=15866:Execution
+ time:TPR015-10:(millisec):33',
                    '100644:MWTP_CAT:12002: SERVER:pid=16565:Execution
+ time:TPR007-12:(millisec):437',
                    '100644:MWTP_CAT:12002: SERVER:pid=16565:Execution
+ time:TPR007-12:(millisec):470',
                    '100644:MWTP_CAT:12002: SERVER:pid=16048:Execution
+ time:TPR009-30:(millisec):24',
                    '100644:MWTP_CAT:12002: SERVER:pid=15866:Execution
+ time:TPR012-01E:(millisec):63',
                    '100644:MWTP_CAT:12002: SERVER:pid=10427:Execution
+ time:ISCST044:(millisec):0',
                    '100644:MWTP_CAT:12002: SERVER:pid=15866:Execution
+ time:TPR012-01E:(millisec):85',
                    '100644:MWTP_CAT:12002: SERVER:pid=10428:Execution
+ time:01201E:(millisec):3',
                );

# create sorted data set
@SortedData = reverse sort { (split (/:/, $a))[-1] <=> (split (/:/, $b
+))[-1] } @Data;

### DEBUG: print input and output sets ###
print "Data Set is:\n", join ("\n", @Data), "\n";
print "Sorted Data is:\n", join ("\n", @SortedData), "\n";
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In reply to Re: Sorting records on a single field by Lain78
in thread Sorting records on a single field by TStanley

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