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I really don't understand your example. I substituted warns with prints:
and this is the result:
The last two lines are NOT equal, because are references to two different scalars. And, as a consequence, $re != $re2 (and $re == $re, but it was expected). So numerical comparison doesn't tell you if two regex are equal, but only if they are the same (reference). Rule One: "Do not act incautiously when confronting a little bald wrinkly smiling man." In reply to Re^2: What is the best way to compare variables so that different types are non-equal?
by psini
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