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And given knowledge of algorithm (use the source), and the current bucket size, (see the second element of scalar %hash), the ordering is knowable; therefore definable; therefore defined by the implementation(s). Actually, you have overlooked the order of items on the linked list of a bucket that holds more than one entry. - tye In reply to Re^11: What makes an array sorted and a hash unsorted? (nit)
by tye
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