Child processes inherit their parent's file handles. So, if you want
to redirect STDOUT to a file in both the parent and the child, you can
do something like this:
close STDOUT;
open STDOUT, ">out" or die;
my $pid = fork();
die "" if !defined $pid;
exit 0 if $pid; # parent exits
print "Message!\n"; #child prints to file
This works as expected and prints to the file, not to STDOUT. You can do something similar by tie()ing the
file handle to a trapper class:
tie *STDOUT, TrapClass;
my $pid = fork();
die "" if !defined $pid;
exit 0 if $pid; # parent exits
print "Message!\n"; # child prints to file
package TrapClass;
sub TIEHANDLE {
my $class = shift;
open(my $fh, ">out") or die;
bless { fh => $fh }, $class;
}
sub PRINT {
my $self = shift;
my $fh = $self->{fh};
print $fh @_;
}
This works as well, printing to the file instead of STDOUT. However, if you replace the print statement by
exec() to overload the child process with something else, like
/bin/date, it doesn't work anymore, the child process will print
to STDOUT, not to the file:
tie *STDOUT, TrapClass;
my $pid = fork();
die "" if !defined $pid;
exit 0 if $pid; # parent exits
exec "/bin/date"; # child prints to STDOUT!!
package TrapClass;
sub TIEHANDLE {
my $class = shift;
open(my $fh, ">out") or die;
bless { fh => $fh }, $class;
}
sub PRINT {
my $self = shift;
my $fh = $self->{fh};
print $fh @_;
}
This is puzzling, given that exec() works just fine if you redirect the file handle the good-old fashioned way:
close STDOUT;
open STDOUT, ">out" or die;
my $pid = fork();
die "" if !defined $pid;
exit 0 if $pid; # parent exits
exec "/bin/date"; #child prints to file
Does anyone know what kind of dark magic is going on in tie() to breaks the third case?
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