I believe that qw// no longer use split in 5.6. Instead,
it's using the comma-operator. As a result, you are just trying
to assign a list to a scalar. Thus, $_ will just hold 'nothing'
and the answer for part c is "In the beginning there was alpha,
in the end there will be omega."
Disclaimer: I don't have 5.6 installed, so the above is
pure speculation. Pls correct me if I'm wrong. : )
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