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Is the behavior of list slice subroutine return an intended feature

A slice is not an array. What you return is what you get. I don't see any magic there. You're definitely right about not golfing production code. This is from a test script however - I allow myself a little more relaxed way of coding in those. :-)

I think I understand the thing now - it's an XY case if I'm correct. That subroutine's return value has been assigned to a scalar and that has been pushed to an array. Maybe this code works differently on 5.6?

sub is_digits { my @rv = $_[0] =~ /^([0-9]+)$/; return @rv[ 0 .. $#rv ]; } my $nothing = is_digits('abc'); my @arr1 = ($nothing); my @arr2 = ('some', 'thing'); push @arr2, @arr1; print "There are ", scalar(@arr2), " elements in \@arr2\n"; print '$arr2[2] is ', defined($arr2[2])?'':'un', "defined\n";

What I expect and get on 5.8.8 is:

There are 3 elements in @arr2 $arr2[2] is undefined

Update: Modified the code to more closely follow the original.

use strict; use warnings; print "Just Another Perl Hacker\n";

In reply to Re: regexp list return 5.6 vs 5.8 by Sixtease
in thread regexp list return 5.6 vs 5.8 by Sixtease

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