ouch... I'm
oha's friend :-)
of course, I tested it with:
# This is perl, v5.8.7
my @a = (1,2,3);
my @b = (4,5,6);
push 1==1 ? @a : @b, "foo";
print "a=@a b=@b\n";
I even counter-checked (!) it with:
push 1==0 ? @a : @b, "foo";
to verify that the "foo" was pushed into @b.
of course, such stupid conditionals are optimized away. sorry for fooling myself,
oha, and probably others. shame on me :-)
cheers,
Aldo
King of Laziness, Wizard of Impatience, Lord of Hubris
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