Like
liverpole, I am not sure what it is you require. Perhaps you need to use the 4 argument form of
splice to, in effect, replace an element without changing it's position.
use strict;
use warnings;
# Set up arrays, use hash to find elements of
# @arrB not duplicated in @arrA.
#
my @arrA = (1, 2, 3, 4);
my @arrB = (1, 5, 3, 6, 8, 2, 4);
my %hashA;
@hashA{@arrA} = ();
my @nonDup = grep { not exists $hashA{$_} } @arrB;
# Show arrays.
#
print
qq{Before\n},
qq{@arrA\n},
qq{@arrB\n},
qq{@nonDup\n};
# Look to replace value 3 in @arrA. Loop over @arrA
# to find the element we want.
#
my $toReplace = 3;
foreach my $idx ( 0 .. $#arrA )
{
next unless $arrA[$idx] == $toReplace;
# Use splice to take the found element out of
# @arrA and replace it with one randomly splice'ed
# out of @nonDup.
#
splice
@arrA,
$idx,
1,
splice
@nonDup,
int rand @nonDup,
1;
last;
}
# Show what we have now.
#
print
qq{After\n},
qq{@arrA\n},
qq{@arrB\n},
qq{@nonDup\n};
The output is
Before
1 2 3 4
1 5 3 6 8 2 4
5 6 8
After
1 2 6 4
1 5 3 6 8 2 4
5 8
Note that I use only three arguments for the second splice as we do not need to replace the element taken out of @nonDup.
I hope this guess is something close to what you need and will be helpful.
Cheers,
JohnGG
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