With one more change, the code works fine:
27,28c27,28
< $s1 =~ /^\d+$/ and $s2 =~ /^\d$/ and
< &$f(10*$v1 + $v2, $s1 . $s2);
---
> $s1 =~ /^\d+$/ && $s2 =~ /^\d$/ and
> &$f($v1 + 10 * $v2, $s1 . $s2);
and the output I see is
24 = (3 * (14 - 6))
24 = (6 / (1 - (3 / 4)))
24 = ((14 - 6) * 3)
which seems quite OK.
Now I haven't looked yet if that's an oneliner in some Perl Golf competition, but I'd bet there is something :)
Would be nice to let us now if in the end you had some personal conclusions about your attempted Ruby/Perl comparison.
Thanks,
Krambambuli
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