I think you can do away with the third condition of ($val1 == $val2).
Tricky one. I thought the same at first.
But think of 0 and 0.0 or 0E0 - all numerically equal, but not sting equal.
Same goes for 1.1 and 1.10 and of course, there's more to think about.
Cheers, Sören
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