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This was actually my first instinct too, here was the output I got from testing with B::Concise.

stvn% perl -MO=Concise -e '$x++' 5 <@> leave[1 ref] vKP/REFC ->(end) 1 <0> enter ->2 2 <;> nextstate(main 1 -e:1) v ->3 4 <1> preinc[t2] vK/1 ->5 - <1> ex-rv2sv sKRM/1 ->4 3 <#> gvsv[*x] s ->4 -e syntax OK stvn% perl -MO=Concise -e '$x += 1' 6 <@> leave[1 ref] vKP/REFC ->(end) 1 <0> enter ->2 2 <;> nextstate(main 1 -e:1) v ->3 5 <2> add[t2] vKS/2 ->6 - <1> ex-rv2sv sKRM/1 ->4 3 <#> gvsv[*x] s ->4 4 <$> const[IV 1] s ->5 -e syntax OK stvn% perl -MO=Concise -e '$x = $x + 1' 8 <@> leave[1 ref] vKP/REFC ->(end) 1 <0> enter ->2 2 <;> nextstate(main 1 -e:1) v ->3 7 <2> sassign vKS/2 ->8 5 <2> add[t3] sK/2 ->6 - <1> ex-rv2sv sK/1 ->4 3 <#> gvsv[*x] s ->4 4 <$> const[IV 1] s ->5 - <1> ex-rv2sv sKRM*/1 ->7 6 <#> gvsv[*x] s ->7 -e syntax OK
You can see that the x += 1 and x = x + 1 are similar, but not enough to call equivalent. Besides I am not sure that opcode equivalence would actually work since perl performs optimizations on the opcode tree during compilation which you would not want to include in your comparisons.


In reply to Re^2: Equivalency of Code by stvn
in thread Equivalency of Code by rkosai

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