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It can be done more efficiently than this. You shouldn't divide the work up evenly. Below are some special cases and the smallest solution sizes possible (I believe) for them. If P is the number of pegs, D is the number of disks, and M is the minimum number of moves for which a solution exists, then:
So I can beat your 35move solution for the 5P10D case by 4 moves. I may write up why this is so, but I suspect someone else is likely to beat me to that. And if you try to figure out why I picked these cases, you'll probably have a good hint for part of a good solution for the general problem. (:  tye In reply to Re^2: Best possible counts for a few test cases (in readmore) (Hanoi Challenge)
by tye

