And to get things going, I'll post the bad solution that everyone should be able to beat. This ignores all but the first 3 pegs.
#! /usr/bin/perl -w
use strict;
my $disk_count = pop;
solve('A'..'C', reverse 1..$disk_count);
sub solve {
my ($peg_from, $peg_to, $peg_hold, $first_disk, @rest) = @_;
return unless $first_disk;
solve($peg_from, $peg_hold, $peg_to, @rest);
print "$first_disk: $peg_from -> $peg_to\n";
solve($peg_hold, $peg_to, $peg_from, @rest);
}
Again, this makes no use of extra pegs, which you can use to beat it.
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